Question

find the number of faces edges and vertices in a prism whose base is a polygon of 10 sides

Answer 1

here's ur ans.....


sides=10
so
no. of faces=12 (10+top +bottom)
no. of edges=30(10bottom +10 top +10sides)
no. of vertices=20(10 bottom +10 top)





this is ur answer

hope it helps u.....

Answer 2

Given:

Sides of the polygonal base=10

To find:

i. The number of faces of the prism

ii. The number of edges of the prism

iii. The number of vertices of the prism

Solution:

The prism has 12 faces, 30 edges, and 20 vertices.

We can find the numbers by following the given steps-

We know that the base of the prism is a 10-sided polygon.

So, the prism is made up of two 10-sided polygons and ten rectangular faces joining the top and base.

i. The number of faces of the prism can be obtained by adding all the faces of the prism formed by joining the polygonal bases.

The number of faces of the prism=Two polygonal faces+Ten rectangular faces

=2+10

=12 faces

ii. The number of edges can be obtained by counting the sides formed to join all the faces.

So, the number of edges of the prism=Number of edges of the two polygonal bases+Number of edges connecting each vertex of both the polygons

The number of edges of the prism=2×10+10

=20+10

=30 edges

iii. The vertices of the prism are the points at which the edges meet.

The number of vertices of the prism=Vertices of each polygonal face

=10+10

=20 vertices

Therefore, the prism has 12 faces, 30 edges, and 20 vertices.