find the number of faces edges and vertices of pyramid with square base verify euler's formula for it
Answers
Answer:
Euler's polyhedron formula, V−E+F=2
V = number of vertices = 5
E = number of edges =?
F = number of faces = 5
Thus 5−E+5=2
⇒E=10−2
⇒E=8
Number of edges = 8
Given : pyramid with square base
To Find : number of faces, edges and vertices
Verify Euler Formula
Solution:
pyramid with square base
4 vertex of Square as base
and 1 vertex at top
=> Total Vertex V = 4 + 1 = 5
On Face is Square
4 faces are ( slanted ) of 4 triangles
Faces F = 1 + 4 = 5
Edges
4 - Edges of Square
3 Edges of one triangle hence 3 x 4 = 12 Edges
But 1 Edge of triangle is common with other triangle
and 1 Edge of triangle is common with Square
Hence 2 x 4 = 8 Edges to be reduced
Edges = 4 + 12 - 8 = 8
Vertex V = 5
Faces F = 5
Edges E = 8
Euler formula for faces
= Edges - Vertex + 2
=> F = E - V + 2
LHS = F = 5
RHS = E - V + 2
= 8 - 5 + 2
= 5
LHS = RHS
Hence Verified
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