Find the number of faces for polyhedron having nine edges and six vertices.
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Answer:
Faces =5
Step-by-step explanation:
GIVEN:
Edges = 9
Verticles =6
Let No of faces be F
According to Euler's Law
F + V -E =2
F + 6 - 9 = 2
F - 3= 2
F = 3 + 2
Faces = 5
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