Physics, asked by sreenivasa328, 3 months ago

Find the number of fringes in the interference pattern which is 7.2mm long​

Answers

Answered by Yogyamalik08
0

Answer:

Wavelength of laser light , λ1=640nmλ1=640nm

Fringe width, β1=8.1mmβ1=8.1mm

Wavelength of second light , λ2=?λ2=?

Fringe width, β2=7.2mmβ2=7.2mm

we know that fringe width is given by

β=Dλdβ=Dλd

since D and d are fixed , β∝λβ∝λ

∴β1β2=λ1λ2∴β1β2=λ1λ2

⇒λ2=β2β1×λ1=7.28.1×640=569nm⇒λ2=β2β1×λ1=7.28.1×640=569nm.

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