Question

Find the number of g atom and weight of an element having 2 x 10*23atoms. (At. Wt. = 32)​

Answer 1

Answer:

No. of g atom (no. of moles)=0.332

mass of element =10.624 g

Explanation:

No. of moles = No. of entites/ Avogadro No.

                     = 2*10^23/6.022*10^23

                     = 0.332

Also, No. of moles = Mass in gram/ Atomic mass

Therefore Mass in gram = Atomic mass* No. of moles

                                        = 32*0.332

                                        = 10.624

Answer 2

Answer:

No. of g atom (no. of moles)=0.332

Mass of element =10.624 g  

Explanation:

No. of moles = No. of entites/ Avogadro No.

                    = 2*10^23/6.022*10^23

                    = 0.332

Also, No. of moles = Mass in gram/ Atomic mass

Therefore Mass in gram = Atomic mass* No. of moles

                                       = 32*0.332

                                       = 10.624

                                             : )