find the number of generators of the cyclic group Zn with addition modilo n
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It is cyclic, since it is generated by the primitive root = + = /: that is, G = z = { 1, z, z 2, z 3, z 4, z 5} with z 6 = 1. Under a change of letters, this is isomorphic to (structurally the same as) the standard cyclic group of order 6, defined as C 6 = g = { e , g , g 2 , g 3 , g 4 , g 5 } with multiplication g j · g k = g j+k (mod 6) , so that g 6 = g 0 = e.
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