Question

find the number of H+ and SO4 2- in 196g aqueous solve of H2SO4

Answer 1

H₂SO₄ ⇔ 2H⁺ + SO₄²⁻
Here it is clear that in one mole of H₂SO₄ , two moles of H⁺ and one mole of SO₄²⁻ are present.
now, firstly we should find out number of moles of H₂SO₄ .
number of moles = given weight of H₂SO₄/molecular weight of H₂SO₄
= 196g/98g/mol = 2 moles

∴ number of moles of H⁺ = 2 × 2 = 4 moles
so, number of ions in H⁺ = number of moles of H⁺ × 6.023 × 10²³
= 4 × 6.023 × 10²³ = 2.4092 × 10²⁴
number of moles of SO²⁻ = 2 moles
number of ions in SO₄²⁻ = number of moles of SO₄²⁻ × 6.023 × 10²³
= 2 × 6.023 × 10²³
= 1.2046 × 10²⁴