Question

Find the number of hydrogen atoms in 9.033*10^23 molecules of water

Answer 1

One molecule of water contains 2 atoms of hydrogen..

So, no of H atoms in 9.033*10^23 molecules of water =

2*(9.033*10^23) atoms= 18.066*10^23

Answer 2

$18.07\times 10^{23}$ atoms of hydrogen are there in $9.033\times 10^{23}$ molecules of water

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles of water}=\frac{\text{Given molecules}}{\text {avogadro's number}}=\frac{9.033\times 10^{23}}{6.023\times 10^{23}}=1.5moles$

1 mole of water $(H_2O)$ contains= $2\times 6.023\times 10^{23}=12.05\times 10^{23}$  atoms of hydrogen

1.5 moles of water $(H_2O)$ contains= $\frac{12.05\times 10^{23}}{1}\times 1.5=18.07\times 10^{23}$ atoms of hydrogen

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