Find the number of integer between 200 and 500 which are divisible by 7
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Answered by
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Let a be the first term and d be the common difference.
The first term between 200 and 500 divisible by 7 is 203 and the last term is 497.
Therefore the first term a = 203 and the common difference d = 7.
We know that sum of n terms of an AP an = a + (n - 1) * d
497 = 203 + (n - 1) * 7
497 = 203 + 7n - 7
497 = 7n + 196
497 - 196 = 7n
301 = 7n
301/7 = n
n = 43.
Therefore, there are 43 integers between 200 and 500 which are divisible by 7.
Hope this helps!
The first term between 200 and 500 divisible by 7 is 203 and the last term is 497.
Therefore the first term a = 203 and the common difference d = 7.
We know that sum of n terms of an AP an = a + (n - 1) * d
497 = 203 + (n - 1) * 7
497 = 203 + 7n - 7
497 = 7n + 196
497 - 196 = 7n
301 = 7n
301/7 = n
n = 43.
Therefore, there are 43 integers between 200 and 500 which are divisible by 7.
Hope this helps!
siddhartharao77:
Thanks for the brainliest
Answered by
45
Heya :::-
This is your answer.
We have to find the number of integers which are divisible by 7 between 200 and 500.
Soooo.....
The multiples of 7 between 200 and 500 are in the form of AP ......
203, 210, 217, ........., 497.
Therefore,
a = 203.
d = 7, and
an = 497.
We know that
an = a + (n-1)d
497 = 203 + (n-1)7
294 = 7(n-1)
42 = n -1
n = 43.
Hence there 43 integers between 200 and 500 which are divisible by 7.
HOPE U GOT IT
This is your answer.
We have to find the number of integers which are divisible by 7 between 200 and 500.
Soooo.....
The multiples of 7 between 200 and 500 are in the form of AP ......
203, 210, 217, ........., 497.
Therefore,
a = 203.
d = 7, and
an = 497.
We know that
an = a + (n-1)d
497 = 203 + (n-1)7
294 = 7(n-1)
42 = n -1
n = 43.
Hence there 43 integers between 200 and 500 which are divisible by 7.
HOPE U GOT IT
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