Find the number of integers between 100 and 1000
1) divisible by 7
2) not divisible by 7
Answers
Answered by
6
105,112,119,………………..994
Here a (first term)=105
d (common difference)=7
an (last term)=994
an=a+(n-1)d
994=105+(n-1)7
994=105+7n-7
994=98+7n
994-98=7n
896=7n
n=896÷7
n=128
There are 128 numbers in between 100 and 1000 which are divisible by 7.
Total number between 100 and 1000 is 899
Hence the total numbers between 100 and 1000 which are not divisible by 7 will be
899-128=771
Here a (first term)=105
d (common difference)=7
an (last term)=994
an=a+(n-1)d
994=105+(n-1)7
994=105+7n-7
994=98+7n
994-98=7n
896=7n
n=896÷7
n=128
There are 128 numbers in between 100 and 1000 which are divisible by 7.
Total number between 100 and 1000 is 899
Hence the total numbers between 100 and 1000 which are not divisible by 7 will be
899-128=771
Haria123:
numbers between 100 and 1000 is 900 we use this method (last term - first term+1)
Answered by
1
Divisible by 7
994=105+7x-7
7x=896
x=128
Not divisible by 7
Terms=1000-100+1= 901
Not divisible= 901-128= 773
994=105+7x-7
7x=896
x=128
Not divisible by 7
Terms=1000-100+1= 901
Not divisible= 901-128= 773
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