Question

Find the number of integers between 21 and 99 divisible by 6

Answer 1

Answer:

number of terms between 21 and 99 divided by 6 is n=13

Step-by-step explanation:

First number divided by 6 is 24 and last is 96

common difference is 6, a=24 and an=96

as

• an=a+(n-1)d

substitute values in general term of A.P

96=24+(n-1)6

96=24+(n-1)696-24=(n-1)6

96=24+(n-1)696-24=(n-1)672/6=n-1

96=24+(n-1)696-24=(n-1)672/6=n-112=n-1

96=24+(n-1)696-24=(n-1)672/6=n-112=n-1n=13

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