Math, asked by shubhikhshaagobi, 9 months ago

Find the number of integers between 60 and 600 which are divisible by 9 or 12​

Answers

Answered by aastha2033
2

Answer:

77 integers between 60 and 600 are divisible by 7.

Step-by-step explanation:

This is a problem in AP. The first number is 63 and the last number is 595, both of which are divisible by 7 and lie between 60 and 600.

Tn = a +(n-1)d

595 = 63 + (n-1)*7, or

595–63 = 532 = 7n - 7, or

532+7 = 539 = 7n, or

n = 539/7 = 77.

Answer: This is a problem in AP. The first number is 63 and the last number is 595, both of which are divisible by 7 and lie between 60 and 600.

Tn = a +(n-1)d

595 = 63 + (n-1)*7, or

595–63 = 532 = 7n - 7, or

532+7 = 539 = 7n, or

n = 539/7 = 77.

Answer: 77 integers between 60 and 600 are divisible by 7.

Answered by chprasanth1305
1

Answer:

Step-by-step explanation:

pick the first num divisible by 9  = 63

last num divisible by 9 & 12 = 594

Tn = a +(n-1)d

Tn = 594

a = 63

594 = 63+(n-1)*9

594 = 63+9n-9

594 = 54+9n

540 = 9n

n = 60

60 integers between 60 and 600 are divisible by 9.

and with 12 try by u r self so that u can understnad the process

or else txt me

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