Question

Find the number of integral pairs of (x, y) for xy - y - 2x = 3​

Answer 1

The Answer is given below

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Step-by-step explanation:

the number of integral pairs of (x, y) for xy - y - 2x = 3 is

Xy + y + -2x + -3 = 0

Reorder the terms: -3 + -2x + y + yX = 0

Solving -3 + -2x + y + yX = 0

Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right.

Add '3' to each side of the equation.

-3 + -2x + y + 3 + yX = 0 + 3

Reorder the terms: -3 + 3 + -2x + y + yX = 0 + 3

Combine like terms: -3 + 3 = 0 0 + -2x + y + yX = 0 + 3 -2x + y + yX = 0 + 3

Combine like terms: 0 + 3 = 3 -2x + y + yX = 3