Question

find the number of integral value of x so that 2 power 2 x square - 7 x + 5 is equal to 1​

Answer 1

Step-by-step explanation:

2x^2-7x+5=1

2x^2-7x+5-1=0

2x^2-7x+4=0 (2x^2-7x+8)

2x^2-(7+1)x+4

(2x^2-7x)(x+4)

Question sahi h

Answer 2

There are two integral values of x.

Step-by-step explanation:

We have,

$2^{x^2-7x+5}=1$

To find, the number of  integral value of x = ?

∴ $2^{x^2-7x+5}=1$

⇒ $2^{x^2-7x+5}=2^0$

Comparing the powers, we get

⇒ $2x^2-7x+5=0$

⇒ $2x^2-5x-2x+5=0$

⇒ $x(2x - 5) - 1(2x - 5) = 0$

⇒(x - 1)(2x - 5) = 0

⇒ x - 1 = 0 or, 2x - 5 = 0

⇒ x - 1 = 0 ⇒ x = 1

⇒ 2x - 5 = 0

⇒ 2x = 5

⇒ x = $\dfrac{5}{2}$

∴ x = 1 or, $\dfrac{5}{2}$

Thus, there are two integral values of x.