Question

Find the number of linesegments can be drawn from 8 poinits such that no three points are collinear

Answer 1

Hey there!

Number of line segments that can be drawn from " n " points such that no three points are co-llinear = n ( n - 1 ) / 2 .

Given,
Number of points = 8 .
So,
n = 8 .

Number of line segments drawn = 8 ( 8 - 1 ) / 2 = 8 * 7 /2 =28 .

$\therefore$ The number of line segments that can be drawn from 8 points such that no three are collinear = 28 .