find the number of marble slabs inch of diameter 40 cm and 20 cm to build around a square park of side 18 metre to a width of 2 metre
Answers
Step-by-step explanation:
The number of marbles is 4032.
Step-by-step explanation:
The dimension of marble slabs is 40 cm× 20 cm.
The area of marble slab is A=l\times bA=l×b
A_m=40\times 20A
m
=40×20
A_m=800\ cmA
m
=800 cm
The square Park of side 18 m to a width of 2 cm.
Convert 18 m into cm,
1\ m = 100\ cm1 m=100 cm
18\ m = 1800\ cm18 m=1800 cm
The actual side of square is s=1800-2-2=1796\ cms=1800−2−2=1796 cm
The area of the square is A=s^2A=s
2
A_s=1796^2A
s
=1796
2
A_s=3225616A
s
=3225616
The number of marbles is given by,
n=\frac{A_s}{A_m}n=
A
m
A
s
n=\frac{3225616}{800}n=
800
3225616
n=4032.02n=4032.02
Therefore, the number of marbles is 4032.
#Learn more :
The number of marble slabs of size 25 cm into 25 CM required to pay the floor of a square room of side 10 M piece.
Answer:
The dimension of marble slabs is 40 cm× 20 cm. The square Park of side 18 m to a width of 2 cm. Therefore, the number of marbles is 4032.