Question

find the number of milliequivalents present in 0.25N sulphuric acid solution.​

Answer 1

Answer:

Milliequivalents = 0.0005

Explanation:

The normality of a solution is the gram equivalent weight of a solute per liter of solution

It is represented using the symbol N, eq/L, or meq/L (= 0.001 N)

Given the above case, one molecule of sulfuric acid, H2SO4, produces two hydrogen ions in the solution

As a result, one molar solution of H2SO4 will have the normality of 2.

It means that the value of N is 2.

Now as per question statement ;

Milliequivalents = 0.001 x 0.25 x 2 = 0.0005