Find the number of molecules, atoms and electrons present in 0.7 grams of Nitrogen
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moles=0.7÷28=0.025
molecules =0.025×6.022×10^23
=1.5055×10^22
atoms=3.011×10^22
electron =3.011×10^22×7
=2.1077×10^23
molecules =0.025×6.022×10^23
=1.5055×10^22
atoms=3.011×10^22
electron =3.011×10^22×7
=2.1077×10^23
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