Question

find the number of molecules in 10cm^3 of an ideal gas at 0 degree celcius and at a pressure of 2×10^-5 mm of mercury. take density of hg=13.6g/cc and g=10m/s^2 R=25/3 j/mol-k​

Answer 1

Answer:

=1cm

3

=10

−3

m

3

T=0

0

C=273K

P=10

−5

mmHg

=133.32×10

−5

N/m

2

R=8.314J/mol.k

PV=nRT (ideal gas eq.)

⇒133.32×10

−5

×10

−6

=n×8.314×273

⇒n=0.0056×10

−11

mol

v=1mol=6.023×10

23

molecules

∴6.023×10

23

×0.056×10

−11

=3.37×10

11

molecules.