Question

Find the number of molecules present in same amount of NH3.​

Answer 1

Answer:

V=5.6 dm

3

=5.6 L

Then ,

We know that,

n=V/22.4

n=5.6/22.4

n=56/224

n=0.25 mole.

And for the no of molecules,

We have a concept,

No. of molecules =n × Avogadro number

No. of molecule =0.25×6.022×10

23

No. of molecules =1.5×10

23