Question

Find the number of moles and molecules present in 7.1 gram of chlorine

Answer 1

Answer:

0.1 moles and 6.023 * 10^22 molecules

Explanation:

We know that, Avogadro's number is numerically equal to 6.023 * 10^23!

Calculating the Relative Molecular Mass of chlorine gas:

RMM of Chlorine gas = 2 * ( 35.5 ) = 71 g

Calculating the Number Of Moles present in 7.1 g of Chlorine:

71 g of Chlorine constitutes 1 mole

=> 7.1 g of Chlorine constitutes { (1/71) * 7.1 } i.e. 0.1 moles.

Calculating the Number of Molecules present in 7.1 g of Chlorine:

1 mole of chlorine contains 6.023 * 10^23 molecules

=> 0.1 moles of chlorine contain ( 6.023 * 10^23 * 0.1 ) i.e. 6.023 * 10^22 molecules.

(Since, 0.1 mole = 7.1 g of chlorine, as proved above in first subpart)

=> 7.1 g of chlorine contains 6.023 * 10^22 molecules.

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