Question

Find the number of moles and number of molecules present in 2.675 gram of ammonium chloride. [Given that atomic mass of N = 14 u, H =1u , Cl= 35.5u ] ​

Answer 1

Answer:

Number of Moles = 0.05

Number of Molecules = 0.3011*10^23

Explanation:

Ammonium Chloride = NH4Cl

Formula unit mass of NH4Cl = 53.5 u

1 mole of NH4Cl ( molar mass ) = 53.5g

Given mass of NH4Cl = 2.675g

Number of Moles = Given mass divided by molar mass

= 0.05 moles

Number of Molecules = number of moles*Avogadro's number

=0.05*6.022*10^23

=0.3011*10^23 molecules