Question

find the number of moles in 75gm CaCO³ (Ca=40u, C=12u, O=​

Answer 1

Correct question:-

Calculate the number of moles in 75g CaCO3(Calcium-Carbonate)

Given:-

•Mass of CaCO3=75g

•Atomic mass of Calcium(Ca)=40u

•Atomic mass of Carbon(C)=12u

•Atomic mass of Oxygen(O)=16u

To find:-

•Number of moles

Solution:-

Molecular mass of CaCO3

=>40+12+16×3

=>40+12+48

=>100u

Since,molecular mass of CaCO3 is 100u,thu it's molar mass is 100g.

Now,we know that:-

=>No of moles=Given mass/Molar mass

=>75/100

=>0.75moles

Thus,0.75 moles are present in 75g CaCO3.