Find the number of moles in 8 g of KOH (K=39u, O=16u, H=1u)
Answers
Step-by-step explanation:
No. of moles in 8g of oxygen atom
n=
M
m
×N
A
⇒
16
8
×6.02×10
23
=3.01×10
23
moles
ii) 6.02×10
23
atoms contains 1 mole
Then, 4.088×10
21
atom contains =
6.02×10
23
4.088×10
21
=0.67×10
−2
moles
Given - Mass of potassium hydroxide - 8 gram
Elemental weight of atoms - K - 39u, O - 16u, H - 1u.
Find - Number of moles in 8 gram of potassium hydroxide.
Solution - Number of moles of compound can be calculated by the formula - Weight of given compound/Molecular weight of given compound.
Molecular weight of potassium hydroxide - 39+16+1
Molecular weight of potassium hydroxide - 56 g/mol
Keeping the values in equation-
Number of moles - 8/56
Number of moles - 0.14.
Hence, number of moles in 8 gram of potassium hydroxide is 0.14