Question

Find the number of moles of the following

a) 85g NH3
b)44.8L CO2​

Answer 1

Explanation:

D

48×1023

Mass of 1 mol or (6.022×1023 molecules) of NH3=14+3×1=17 g

Number o f molecules in 34 g NH3=1734×6.022×1023=12.044×1023

Number of atoms present in 1 molecule of NH3=4

Number of atoms in 34 g NH3=4×12.044×1023

                                                      ≈48×1023

option D is correct