Question

Find the number of moles present in 11.1 GM's of cacl2​

Answer 1

Answer:

cacl2 (40 + 35×2 ) = 110 gm

110gm = 1 mol of cacl2 = 6.022× 10^23 atom

11.1gm = 11.1/110 mol= 0.1009 mol

Answer 2

Answer:

cacl2 (40 + 35×2 ) = 110 gm

110gm = 1 mol of cacl2 = 6.022× 10^23 atom

11.1gm = 11.1/110 mol= 0.1009 mol

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