Question

Find the number of moles present in the following;- 1 ] 2.7 gm of aluminum 2 ] 18 gm of glucose 3 ] 1 gm atom of hydrogen 4 ] 4 gm molecules of chlorine 5 ] 1.8 * 10^(23) molecules of oxygen 6 ] 3 * 10^(22) atoms of hydrogen 7 ] 5.6L of helium at S.T.P 8 ] 4.48L of ozone at S.T.P

Answer 1

Answer:

sorry i didnt understood your question

Answer 2

Explanation:

dear friend,

(1)number of moles=given weight/gram molecular weight,so 2.7/27=0.1 mole

(2)number of moles=given weight /gram molecular weight so,18/180=0.1 mole

(3)For any element 1 gram atom=1mole

2 gram atoms=2 moles so, answer is 1 mole

(4)chlorine molecular weight =35 so,35 gram molecules=1 mole so,4 gram molecules=1/35*4=0.11 mole

(5)number of moles=given no of molecules/Na(6.023*10^23) so,1.8*10^23/6*10^23=0.3 moles

(6)number of moles=given no of molecules/Na(6.023*10^23) so,3*10^22/6*10^23=1/20=0.05 moles

(7)number of moles=given volume/22.4 litres

so,5.6/22.4=0.25

(8)number of moles=given volume/22.4 litres

so,4.48/22.4=0.2 moles

hope it helps you

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