find the number of na+ and cl- ions present in 117g sodium chloride na =23 cl=35.5
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Answered by
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Answer:
total weight of na and cl =23+35.5
=58.5
no.of na and cl ions present in 117 g = 117 / 58.5
=2
Answered by
1
The number of sodium and chloride ion present in 117 gram of sodium chloride is equal to 12.046x10²³
Explanation:
- The molecular formula of sodium chloride is NaCl. as a result of this the molecular weight of sodium chloride is 23 + 35.5 = 58.5.
- Therefore in 117 gram of sodium chloride there is 2 x avogadro number of each of the following iron which constitutes sodium chloride. = 2x6.023 x10²³ = 12.046x10²³
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