find the number of natural between 101 and 999 which are divisible by both 2and 5.
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List of natural numbers between 101 and 999 which are divisible by both 2 and 5 :
110, 120, 130, 140, .... 990
This forms an AP (Arithmetic Progression)
First term (a) = 110
Common Difference (d) = 120 - 110 = 10
We already know that,
Nth term of an AP = a + (n - 1) d
990 = 110 + (n - 1) 10
880 = (n - 1) 10
(n - 1) = 88
n = 89
Therefore, there are 89 natural numbers between 101 and 999 which are divisible by both 2 and 5.
110, 120, 130, 140, .... 990
This forms an AP (Arithmetic Progression)
First term (a) = 110
Common Difference (d) = 120 - 110 = 10
We already know that,
Nth term of an AP = a + (n - 1) d
990 = 110 + (n - 1) 10
880 = (n - 1) 10
(n - 1) = 88
n = 89
Therefore, there are 89 natural numbers between 101 and 999 which are divisible by both 2 and 5.
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