Question

find the number of natural number between 102 and 998 which are divisible by 2 and 5 both​

Answer 1

a=t¹=110

tn= 990

d=10

tn= a+ (n-1)d

990=110+(n-1)10

10n-10=990-110

10n-10=880

10n=880+10

10n=890

n=89

therefore, 89 number of natural number between 103 and 990 are divisible by 2 and 5 both .

Thank You

Answer 2

Answer:

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