Math, asked by malhotrarhythm1309, 5 months ago

Find the number of natural number solutions to a + b + c + d = 20 such that …

i. … each of a, b, c and d are even
ii. … each of a, b, c and d are odd​

Answers

Answered by trivenik745
2

2+4+6+8= 20 1st answerrrr.

1+3+5+11=20. 2nd answerrrr

Step-by-step explanation:

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