find the number of natural numbers between 101 and 999 which are divisible by both 2 and 5
Answers
Answered by
3
89 would be the correct answer
Answered by
2
the natural numbers between 101 and 999which are divisible by both 2 and 5 are
110,120,130,.......990it is in arithmetic progression
a=110 and d=10
nth term 990
so there are 89 numbers
110,120,130,.......990it is in arithmetic progression
a=110 and d=10
nth term 990
so there are 89 numbers
Attachments:
Similar questions