Question

find the number of natural numbers between 102 and 998 which are divisible by 2

can anyone answer this question pls.......​

Answer 1

Answer:

Step-by-step explanation:

102+(n-1)2=998

102+ 2n-2=998

2n= 998+2-102

2n= 898

n= 449

Answer 2

Answer:

447

Step-by-step explanation:

We have to take the natural numbers between 102 and 998 and not including them.

Hence, the natural numbers between 102 and 998 which are divisible by 2 are, 104, 106, 108,..........., 996.

This is an A.P. series with first term 104, and common difference 2.

Let us assume that the number of terms in this series is n.

Then we can write, 104+(n-1)2=996

⇒ 2(n-1)= 892

⇒ n-1 =446

⇒ n= 446+1 =447.

Therefore, there are 447 numbers of natural numbers. (Answer)