Question

find the number of natural numbers between 102 and 998 which are divisible by 2 and 5 both​

Answer 1

$\fontsize{18}{10}{\textup{\textbf{The required number is 89}}}$

Step-by-step explanation:

The numbers which are divisible by 2 and 5 are the multiples of (2*5) =10

because 2 and 5 are both prime

So the number of natural numbers divisible by 10 is (998-102)/10

=886/10=88.6~89

rounding off, we get 89 numbers

Another method

lowest number 110 and highest number=990

Dividing by 10 we get 11 and 99

So the number of numbers is 99-11+1=89(+1 because we are including both extreme values)