Find the number of natural numbers between 102 and 998 which are divisible by 2 and 5
both.
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Answer:89
Step-by-step explanation: It should be divisible by 2*5=10
a=110 d=10 an=990
a+(n-1)d=an
110+(n-1)10=990
(n-1)10=880
(n-1)=88
n=89
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