Question

find the number of natural numbers between 102 and 998 which are divisible by both 2&5​

Answer 1

Step-by-step explanation:

As the numbers are divisible by both 2 and 5,so their last digit will always be 0. hence the series are 110,120,130,....,990

here a=110,d=10,an=990

an=a+(n-1)d

990=110+(n-1)10

(n-1)10=880

n-1=88

n=88+1

n=89.

thus the number of natural numbers between 102 and 998 which are divisible by both 2 and 5 is 89.