Question

find the number of natural numbers lies between 101 and 999 which are divisible by both 2 and 5
please give me the answer step by step. (need to write in classwork )​

Answer 1

Answer:

Step-by-step explanation:

The list of numbers between 101 and 999 that are divisible by 2 and 5 are:

110,120,130,...990

The numbers are in A.P, with first term, a=110, common difference, d=10

Last term, a  

n

​

=990

We know that, a  

n

​

=a+(n−1)d

990=110+(n−1)10

⇒990–110=10n–10

⇒880+10=10n

⇒890=10n

⇒n=89

Therefore, the number of terms between 101 and 999 that are divisible by 2 and 5 are 89.

Answer 2

Step-by-step explanation:

the total number of natural numbers which are divisible by both 2 and 5 (or divisible by 10) between 101 and 999 are 89.

thank u roshni

mark me as brainly plz