Question

Find the number of natureal number between 102 and 998 divisible by 3

Answer 1

Answer:

a = 102, d = 3, an = 996

an = a + (n-1)d

996 = 102 + ( n-1) *3

996 - 102 = (n-1) * 3

894/3 = (n-1)

n = 298 + 1

So, n = 299