Question

Find the number of non perfect squared numbers lies between the squares
of 4 and 5
(a)
5
(b) 6
(c) 7
(d)8
PLS TELL THE ANSWER GUYS​

Answer 1

Answer:

ANSWER

Both n

2

and (n+1)

2

are perfect square numbers and they are consecutive perfect squares.

⇒ All the numbers between them are non-perfect square.

Numbers between n

2

and (n+1)

2

are

=(n+1)

2

−n

2

−1

=n

2

+2n+1−n

2

−1

=2n

⇒ There are 2n non-perfect square number

Answer 2

Answer:

5=25

6=36

7=49

8=64

9=81

10=100