Find the number of non zero integral solutions of the equation
(1 Point)
|2+ | =5 |2+i | x=5 x
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Giving ∣1−2i∣
x
=5
x
We need to find value of
′
x
′
for which should be an integer but not zero.
Let first find value of ∣1−2i∣
∴∣1−2i∣=
(1)
2
+(2)
2
=
5
[z=x+iy ⇒∣z∣=
x
2
+y
2
]
Hence ∣1−2i∣
x
=5
x
⇒(
5
)
x
=5
x
∴(
5
)
x
+(
5
)
2x
Comparing powers
→x=2x
→x−2x=0
−x=0
x=0
Hence no non-zero integral solutions.
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