Find the number of numbers between 100 to 200 that are divisible by 3.
Answers
Answered by
0
Answer:
plzz give me brainliest ans and plzzzz follow me
Attachments:
Answered by
0
Answer:
33
Step-by-step explanation:
smallest no. divisible by 3 between 100-200 is 102 largest no. 198
so a1 = 102 an= 198 d = 3
198= 102+(n-1)3
198-102=( n-1)3
96=(n-1)3
96/3= n-1
32= n-1
33 =n
Similar questions