Question

Find the number of numbers formed with the digits 0 2 4 6 8 without repetition that the greater than 4000

Answer 1

25 must be the required number for your answer.

Answer 2

The number of numbers formed with the digits 0, 2, 4, 6, 8 without repetition that the greater than 4000 is 192.

Step-by-step explanation:

To find : The number of numbers formed with the digits 0, 2, 4, 6, 8 without repetition that the greater than 4000 ?

Solution :

We are having digits 0, 2, 4, 6, 8.

Numbers greater than 4000 are to be formed using these digits without repetition.

The number can have 4 digits but greater than 4000 or can have 5 digits.

Total number of 4 digits number greater than 4000 are,

[tex]3\times  ^4 P_3  =3\times 24=72[/tex]

Total number of 5 digits numbers =  $^5P_5 =5!=120$

So, Total number of required numbers =120+72=192

Hence, the number of numbers formed with the digits 0, 2, 4, 6, 8 without repetition that the greater than 4000 is 192.

#Learn more

The sum or the digits of a two digit number is 8 and difference between the number formed and that formed by reversing the digits is 18 .find the number

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