Question

find the number of odd days in 49 years​

Answer 1

Answer:

Step-by-step explanation:

Basic formula for Calendar

Solution: Odd days till January 26, 1950 = Odd days for 1600 yr + Odd days for 300 yr + Odd days for 49 yr + Odd days of 26 days of January 1950. = 0 + 1 + (12 × 2 + 37) + 5 = 67 days = 9 weeks and 4 days = 4 odd days.

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Answer 2

Answer:

Required number of odd days in 49 years are 5.

Step-by-step explanation:

Counting odd days and calculating day of any particular date

1 ordinary year = $= 365 \: days$ = $(52 \: weeks \: + 1 \: days)$

Hence, total number of odd days in 1 ordinary year $= 1$

We know,

1 leap year = 366 days$= 52 \: weeks \: + 2 \: days$

Hence number of odd days in 1 leap year $= 2$

Now given year is 49.

So,49 years = (37 ordinary years + 12 leap years) $= (37 \times 1 + 12 \times 2)$

odd days = 61 odd days = $8 \: weeks \: + 5 \: days$ = 5 odd days.

Extra information,

• 1 year $= 365 \: days$
• 1 years $= 12 \: months$
• 1 month$= 30 \: days$
• 1 week $= 7days$
• 1 days $= 24 \: hours$
• 1 hours $= 60 \: minutes$
• 1 minute $= 60 \: seconds$

This is a Algebra problem,

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