Question

Find the number of odd factors of 14400.​

Answer 1

14,400 = 26 x 32 x 52

d(n) = (a + 1)(b + 1)(c + 1)

d(14400) = (6 + 1)(2 + 1)(2 + 1)

d(14400) = (7)(3)(3)

d(14400) = 63

Answer 2

Answer:

total number of odd factors is 63

Step-by-step explanation:

To locate an ordinary aspect, you want to exclude the even high aspect 2. whereas, the high factorization of a hundred thirty five does now no longer comprise the high aspect 2, so a hundred thirty five has no even elements, all elements are ordinary. Thus, the variety of ordinary elements relies upon at the high aspect 2 of high factorization of any variety.

Let N be the number whose prime factorization is 2ᵃ x qᵇ x r ^c

Then the total number of odd factors are (b+1) (c+1)

Given

number = 14400

solution

prime factorization of 14400

14,400 = 26 x 32 x 52

d(n) = (a + 1)(b + 1)(c + 1)

d(14400) = (6 + 1)(2 + 1)(2 + 1)

d(14400) = (7)(3)(3)

d(14400) = 63

total number of odd factors is 63

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