Find the number of odd multiples of 3 lying between 2 and 100..
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Answer:
Step-by-step explanation:
The odd integers between 2 and 100 which are divisible by 3 are 3, 9, 15, 21, ..., 99.
Here, a=3 and d=6.
a
n
=99
⇒a+(n−1)d=99
⇒3+(n−1)×6=99
⇒6(n−1)=96
⇒n−1=16
⇒n=17
Therefore,
Required sum =
2
n
(a+l)=
2
17
(3+99)=867
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