Find the number of ordered pairs of positive integers (x, y) that satisfy the equation (1/x) +(1/y)= 1/2004.
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Answer:
This can be rewritten as
1x+1y=1n
1x+1y=1n
1y=1n−1x
1y=1n−1x
y=nxx−n
y=nxx−n
Changing variables to k=x−nk=x−n:
y=n(n+k)k
y=n(n+k)k
y=n2k+n
y=n2k+n
The left side is an integer. What does that tell you about the allowed values of kk, and the corresponding number of valid xx values
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