Question

Find the number of ordered pairs of real numbers (x, y) that satisfy x + y +root x+ root y = 56 and x – y +root x - root y = 30.

Answer 1

Answer:

$2(x + \sqrt{x } ) = 86 \\ = > x + \sqrt{x} = 43 \\ = > \sqrt{x} = 43 - x \\ s.o.b.s \\ = > x = {(43 - x)}^{2} \\ = > x = {(43)}^{2} + {x}^{2} - 86x \\ = > {x}^{2} - 87x + 1849 = 0 \\ therefore \: x \: has \: 2 \: roots \\ similarly \: y \: has \: 2 \: roots$

Step-by-step explanation:

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