find the number of ordered triples abc of positive integers such that a *b * c= 108
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We begin by writing the prime product of 108.
108 = 2 × 2 × 3 × 3 × 3
We can obtain 3 ordered triplets as follows :
2 × 6 × 9 = 108
3 × 4 × 9 = 108
2 × 3 × 18 = 108
So we have three ordered triplets.
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