Math, asked by tshering8594, 1 year ago

find the number of ordered triples abc of positive integers such that a *b * c= 108

Answers

Answered by santy2
7

We begin by writing the prime product of 108.

108 = 2 × 2 × 3 × 3 × 3

We can obtain 3 ordered triplets as follows :

2 × 6 × 9 = 108

3 × 4 × 9 = 108

2 × 3 × 18 = 108

So we have three ordered triplets.

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