Question

find the number of oscillations performed per unit by magnet is vibrating in the plane of a uniform field of 1.6 ×10 raised to 5 Wb meter to square the magnet has moment of inertia 3×10 raised to 6 kg /m. square and magnetic moment 3Am square​

Answer 1

Explanation:

we know that, the relationship between time period of an oscillating magnet in a uniform magnetic field is given by,

T = 2π √(I/MB)

So, frequency will be 1/T

thus,

f= (1/2π)*√(I/MB)

putting given values,

f= 1/2π * √(3*10^6)/3*1.6*10^5)

f = 1/2π * √(6.25)

f = 1/2π* 2.5

thus,

f = 0.34 Hz