Question

find the number of oxygen and Aluminium ions in 1.02 gram of Aluminium oxide​

Answer 1

Given;

W = 1.02 g

M = 54 + 48 = 102 g/mol.

let NA = 6 × 10²³ for approximate value

Thus moles of Al2O3 ;

• n = W/M
• n=1.02/102
• n=1/100 moles

1 moles = 2 Al3+ ions and 3 O2- ions

Thus moles of Al3+ ions;

• n×2 = 1/50mol.

Thus no. of Al3+ ions;

• 1/50 × NA = 1/50 × 6 × 10²³
• 0.12 × 10²³ ions

Thus moles of O2-;

• n×3 = 3/100 = 0.03 moles

Thus no of O2- ions;

• 0.03 × NA = 0.03 × 6 × 10²³
• 0.18 × 10²³ ions

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